b^2+2b-80=0

Solution for b^2+2b-80=0 equation:

Simplifying
b2 + 2b + -80 = 0

Reorder the terms:
-80 + 2b + b2 = 0

Solving
-80 + 2b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(-10 + -1b)(8 + -1b) = 0

Subproblem 1
Set the factor '(-10 + -1b)' equal to zero and attempt to solve:

Simplifying
-10 + -1b = 0

Solving
-10 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '10' to each side of the equation.
-10 + 10 + -1b = 0 + 10

Combine like terms: -10 + 10 = 0
0 + -1b = 0 + 10
-1b = 0 + 10

Combine like terms: 0 + 10 = 10
-1b = 10

Divide each side by '-1'.
b = -10

Simplifying
b = -10
Subproblem 2
Set the factor '(8 + -1b)' equal to zero and attempt to solve:

Simplifying
8 + -1b = 0

Solving
8 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-8' to each side of the equation.
8 + -8 + -1b = 0 + -8

Combine like terms: 8 + -8 = 0
0 + -1b = 0 + -8
-1b = 0 + -8

Combine like terms: 0 + -8 = -8
-1b = -8

Divide each side by '-1'.
b = 8

Simplifying
b = 8
Solution
b = {-10, 8}